Can U Prove 3=2 ??

[deluxdon]

This seems to be an anomaly or whatever u call in mathematics.

It seems, Ramanujam found it but never disclosed it during his life time and
that it has been found from his dairy.

See this illustration:

-6 = -6

9-15 = 4-10

adding 25/4 to both sides:

9-15+25/4 = 4-10+25/4

Changing the order

9+25/4-15 = 4+25/4-10

(this is just like a square + b square - two a b = (a-b)square.)

Here a = 3, b=5/2 for L.H.S and a =2, b=5/2 for R.H.S.

So it can be expressed as follows:

(3-5/2)(3-5/2) = (2-5/2)(2-5/2)

Taking positive square root on both sides:

3 - 5/2 = 2 - 5/2

3 = 2 ????????

DON
unk:

 

[andrej]

Changing the order

9+25/4-15 = 4+25/4-10

(this is just like a square + b square - two a b = (a-b)square.)

I think in this point the trick is done - this wouldn't work.

 

[SkinnerW]

I don't see how did you came from this:

9+25/4-15 = 4+25/4-10

to this: (3-5/2)(3-5/2) = (2-5/2)(2-5/2)...

 

[Shadab]

=> 9 + 25/4 - 15 = 4 + 25/4 - 10

=> 3^2 + (5/2)^2 - (2*3*5/2) = 2^2 + (5/2)^2 - (2*2*5/2)

Using Property : a^2 + b^2 - 2ab = (a-b)^2

=> (3 - 5/2)^2 = (2 - 5/2)^2

=> (3 - 5/2)(3 - 5/2) = (2 - 5/2)(2 - 5/2)

 

[SkinnerW]

So which is the correct formula??

Shadab has: a^2 + b^2 + 2ab = (a+b)^2

And Don has: a^2 + b^2 - 2ab = (a-b)^2

Sorry it has been over 20 years since I've done this stuff...

 

[Shadab]

Sorry. I used [a^2 + b^2 - 2ab = (a-b)^2]

but posted [a^2 + b^2 + 2ab = (a+b)^2] earlier in my post.

Corrected it now.

 

[arora]

Good God ! that's way too complex for me ! :sweat:

 

[fpforumstrike]

wow some major math whiz kids in here!! Very nice work I still don't know how you came up with that

 

[amit87]

Yes it's mathematics and there are many ways to get a same answer, but, i am not that genius as Don seems to be..

 

[remoradea]

Is there a close connection between mathematics and webmaster world?

I bet many have to say something about this!

 

[ardit217]

what kind of math is this? like advanced calculus or some crazy trigonometry?

edit: woot woot my 100th post